Thus, breaking le{rsa cannot be equivalent to factoring under algebraic reductions (unless factoring is easy). Essentially, algebraic reductions are restricted to only perform arithmetic operations. They are not allowed to aggressively manipulate bits, e.g. given x; y G ZN they cannot compute x y.
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We provide evidence that breaking low-exponent RSA cannot be equivalent to factoring integers. We show that an algebraic reduction from factoring to breaking ...
May 25, 2006 · We provide evidence that breaking low-exponent RSA cannot be equivalent to factoring integers. We show that an algebraic reduction from ...
May 9, 2021 · We provide evidence that breaking low-exponent RSA cannot be equivalent to factoring integers. We show that an algebraic reduction from factoring to breaking ...
Nov 24, 2014 · Supporting the position that breaking RSA is easier than factoring, if factoring is easy then the RSA secret key may be obtained from the public ...
It is shown that an algebraic reduction from factoring to breaking low-exponent RSA can be converted into an efficient factoring algorithm, and suggests an ...
Jan 26, 2018 · The focus of research into breaking RSA has been on factoring the semiprime, which is a very hard problem. (It was picked because it is a hard ...
In this paper, we show that breaking RSA generically is as hard as factoring the RSA modulus.
The International Association for Cryptologic Research (IACR) is a non-profit scientific organization whose purpose is to further research in cryptology and ...
Jan 1, 2019 · No. These algorithms break discrete logarithms over small- and medium-characteristic fields. RSA is based on factoring and not on discrete ...