Java Program to Find LCM of Two Numbers
Last Updated :
22 Apr, 2024
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LCM (i.e. Least Common Multiple) is the largest of the two stated numbers that can be divided by both the given numbers. In this article, we will write a program to find the LCM in Java
Java Program to Find the LCM of Two Numbers
The easiest approach for finding the LCM is to Check the factors and then find the Union of all factors to get the result.
Below is the implementation of the above method:
// Java Program to find
// the LCM of two numbers
import java.io.*;
// Driver Class
class GFG {
// main function
public static void main(String[] args)
{
// Numbers
int a = 15, b = 25;
// Checking for the largest
// Number between them
int ans = (a > b) ? a : b;
// Checking for a smallest number that
// can de divided by both numbers
while (true) {
if (ans % a == 0 && ans % b == 0)
break;
ans++;
}
// Printing the Result
System.out.println("LCM of " + a + " and " + b
+ " : " + ans);
}
}
Output
LCM of 15 and 25 : 75
Using Greatest Common Divisor
Below given formula for finding the LCM of two numbers ‘u’ and ‘v’ gives an efficient solution.
u x v = LCM(u, v) * GCD (u, v)
LCM(u, v) = (u x v) / GCD(u, v)
Here, GCD is the greatest common divisor.
Below is the implementation of the above method:
// Java program to find LCM
// of two numbers.
class gfg {
// Gcd of u and v
// using recursive method
static int GCD(int u, int v)
{
if (u == 0)
return v;
return GCD(v % u, u);
}
// LCM of two numbers
static int LCM(int u, int v)
{
return (u / GCD(u, v)) * v;
}
// main method
public static void main(String[] args)
{
int u = 25, v = 15;
System.out.println("LCM of " + u + " and " + v
+ " is " + LCM(u, v));
}
}
Output
LCM of 25 and 15 is 75
Complexity of the above method:
Time Complexity: O(log(min(a,b))
Auxiliary Space: O(log(min(a,b))