Linear search using Multi-threading
Last Updated :
25 Jul, 2023
Improve
Given a large file of integers, search for a particular element in it using multi-threading.
Examples:
Input : 1, 5, 7, 10, 12, 14, 15, 18, 20,
22, 25, 27, 30, 64, 110, 220
Output :if key = 20
Key element found
Input :1, 5, 7, 10, 12, 14, 15, 18, 20,
22, 25, 27, 30, 64, 110, 220
Output :if key = 202
Key not present
Prerequisite : Multi-threading
Approach : First create n threads. Then, divide array in to four parts one section for each thread and apply linear search on individual section using multithreading and check whether the key element is present or not.
Command : g++ -pthread linear_thread.cpp
C++
// CPP code to search for element in a // very large file using Multithreading #include <iostream> #include <pthread.h> using namespace std; // Max size of array #define max 16 // Max number of threads to create #define thread_max 4 int a[max] = { 1, 5, 7, 10, 12, 14, 15, 18, 20, 22, 25, 27, 30, 64, 110, 220 }; int key = 202; // Flag to indicate if key is found in a[] // or not. int f = 0; int current_thread = 0; // Linear search function which will // run for all the threads void * ThreadSearch( void * args) { int num = current_thread++; for ( int i = num * (max / 4); i < ((num + 1) * (max / 4)); i++) { if (a[i] == key) f = 1; } } // Driver Code int main() { pthread_t thread [thread_max]; for ( int i = 0; i < thread_max; i++) { pthread_create(& thread [i], NULL, ThreadSearch, ( void *)NULL); } for ( int i = 0; i < thread_max; i++) { pthread_join( thread [i], NULL); } if (f == 1) cout << "Key element found" << endl; else cout << "Key not present" << endl; return 0; } |
Java
// Java code to search for element in a // very large file using Multithreading import java.util.concurrent.*; public class Main { // Max size of array static final int max = 16 ; // Max number of threads to create static final int thread_max = 4 ; static int [] a = { 1 , 5 , 7 , 10 , 12 , 14 , 15 , 18 , 20 , 22 , 25 , 27 , 30 , 64 , 110 , 220 }; static int key = 202 ; // Flag to indicate if key is found in a[] // or not. static int f = 0 ; static int current_thread = 0 ; // Linear search function which will // run for all the threads static void ThreadSearch( int num) { for ( int i = num * (max / 4 ); i < ((num + 1 ) * (max / 4 )); i++) { if (a[i] == key) f = 1 ; } } // Driver Code public static void main(String[] args) { ExecutorService executor = Executors.newFixedThreadPool(thread_max); for ( int i = 0 ; i < thread_max; i++) { executor.execute( new Runnable() { public void run() { ThreadSearch(current_thread++); } }); } executor.shutdown(); while (!executor.isTerminated()) { // Wait for all threads to complete } if (f == 1 ) System.out.println( "Key element found" ); else System.out.println( "Key not present" ); } } // This code is contributed by shivhack999 |
Python3
import concurrent.futures # Max size of array max_val = 16 # Max number of threads to create thread_max = 4 a = [ 1 , 5 , 7 , 10 , 12 , 14 , 15 , 18 , 20 , 22 , 25 , 27 , 30 , 64 , 110 , 220 ] key = 202 # Flag to indicate if key is found in a[] or not f = 0 # Linear search function which will run for all the threads def thread_search(num): global f for i in range (num * (max_val / / 4 ), (num + 1 ) * (max_val / / 4 )): if a[i] = = key: f = 1 break # Driver Code if __name__ = = '__main__' : with concurrent.futures.ThreadPoolExecutor(max_workers = thread_max) as executor: for i in range (thread_max): executor.submit(thread_search, i) if f = = 1 : print ( "Key element found" ) else : print ( "Key not present" ) # This code is contributed by shiv1o43g |
C#
using System; using System.Threading; namespace ThreadSearchDemo { class Program { // Max size of array const int max = 16; // Max number of threads to create const int thread_max = 4; static int [] a = { 1, 5, 7, 10, 12, 14, 15, 18, 20, 22, 25, 27, 30, 64, 110, 220 }; static int key = 202; // Flag to indicate if key is found in a[] or not. static int f = 0; static int current_thread = 0; // Linear search function which will run for all the threads static void ThreadSearch() { int num = Interlocked.Increment( ref current_thread) - 1; for ( int i = num * (max / 4); i < ((num + 1) * (max / 4)); i++) { if (a[i] == key) Interlocked.Exchange( ref f, 1); } } // Driver Code static void Main( string [] args) { Thread[] thread = new Thread[thread_max]; for ( int i = 0; i < thread_max; i++) { thread[i] = new Thread(ThreadSearch); thread[i].Start(); } for ( int i = 0; i < thread_max; i++) { thread[i].Join(); } if (f == 1) Console.WriteLine( "Key element found" ); else Console.WriteLine( "Key not present" ); Console.ReadKey(); } } } |
Javascript
// Max size of array const max_val = 16; // Max number of threads to create const thread_max = 4; const a = [1, 5, 7, 10, 12, 14, 15, 18, 20, 22, 25, 27, 30, 64, 110, 220]; const key = 202; // Flag to indicate if key is found in a[] or not let f = 0; // Linear search function which will run for all the threads function thread_search(num) { for (let i = num * (max_val / 4); i < (num + 1) * (max_val / 4); i++) { if (a[i] === key) { f = 1; break ; } } } // Driver Code for (let i = 0; i < thread_max; i++) { thread_search(i); } if (f === 1) { console.log( "Key element found" ); } else { console.log( "Key not present" ); } |
Output:
Key not present
Exercise: The above code divides array into four subarrays. Extend this to take a parameter that decides number of divisions (or threads).