Program to convert Java list of Shorts to an Indexed Sequence in Scala
Last Updated :
14 Jan, 2020
Improve
A java list of Shorts can be converted to an Indexed Sequence in Scala by utilizing toIndexedSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#
// Scala program to convert Java list // to an Indexed Sequence in Scala // Importing Scala's JavaConversions object import scala.collection.JavaConversions._ // Creating object object GfG { // Main method def main(args:Array[String]) { // Creating list of Shorts in Java val list = new java.util.ArrayList[Short]() // Adding Shorts to the list list.add(100) list.add(1000) list.add(301) // Converting list to an Indexed Sequence val ind = list.toIndexedSeq // Displays Indexed Sequence println(ind) } } |
Output:
Vector(100, 1000, 301)
Example:2#
// Scala program to convert Java list // to an Indexed Sequence in Scala // Importing Scala's JavaConversions object import scala.collection.JavaConversions._ // Creating object object GfG { // Main method def main(args:Array[String]) { // Creating list of Shorts in Java val list = new java.util.ArrayList[Short]() // Adding Shorts to the list list.add(-111) list.add(-1000) list.add(-123) // Converting list to an Indexed Sequence val ind = list.toIndexedSeq // Displays Indexed Sequence println(ind) } } |
Output:
Vector(-111, -1000, -123)
