3. Results
Let
be an epireflective subcategory of
that contains only abelian groups. Our goal is to describe maximal hereditary coreflective subcategories of
that are not bicoreflective in
. It is well known that if a coreflective subcategory
of
contains the
-reflection
of the discrete group of integers, then it is bicoreflective in
(see [
6] (Proposition 16.4)). It is easy to see that also the converse holds if
is a discrete group (see [
4]). Now we show that it holds also in other cases. The case of discrete groups is included for the sake of completeness.
Lemma 1. Let be an epireflective subcategory of such that the -reflection of the discrete group of integers is one of the following:
- 1.
a finite cyclic group,
- 2.
the discrete group of integers,
- 3.
the indiscrete group of integers,
- 4.
the group of integers with the topology generated by its subgroups of the form , where , and P is a given set of prime numbers.
Then a coreflective subcategory of is bicoreflective in if and only if it contains the group .
Proof. Let be a bicoreflective subcategory of . We show that the -coreflection of the group is homeomorphic to . Let be the group for some and be the -coreflection of . Assume it is not surjective. Then for some , , . Let be the subgroup of generated by . There exists a continuous homomorphism such that . Let be the trivial homomorphism. Then but . Hence c is not an epimorphism, a contradiction. It follows that c is bijective. The identity considered as a map is continuous, hence .
Now let be the group of integers with one of the topologies specified in the lemma. Consider the -coreflection . The image of under c is a non-trivial subgroup of (otherwise c would not be an epimorphism). Note that the topologies on specified in the lemma (part 2–4) have the property that all the non-trivial subgroups of are homeomorphic to . Hence the image of is homeomorphic to . It follows from the definition of reflection that the topology on is the finest topology on the group of integers in the subcategory , therefore also is homeomorphic to . □
Corollary 1. Let be an epireflective subcategory of such that and is the group of integers with the indiscrete topology. Let be the subcategory of consisting of all torsion groups from . Then is the largest hereditary coreflective subcategory of that is not bicoreflective in .
We will need also the following lemma:
Lemma 2. Let be an epireflective subcategory of and be a monocoreflective subcategory of . Then is bicoreflective in if and only if the -coreflection of is an -epimorphism.
Proof. Clearly, if
is bicoreflective in
, then the
-coreflection of
is an
-epimorphism. Assume that the
-coreflection
of
is an epimorphism. We will show that the
-coreflection
for an arbitrary group
G from
is an epimorphism. Let
H be a group from
and
be homomorphisms such that
. For every
let
be a group isomorphic to
and
be the homomorphism given by
. Moreover, let
be the
-coreflection of
. Then
is an epimorphism. There exists a unique homomorphism
such that the following diagram commutes:
We have . But h is an epimorphism, therefore and is an epimorphism. □
In the following example we show that Lemma 1 does not hold in general.
Example 1. Let Z be the group of integers with the topology generated by the subgroup and be the smallest epireflective subcategory containing Z. Then consists of subgroups of products of the form , where each is isomorphic to the group Z. Let be the subcategory consisting of all indiscrete groups from . The -coreflection of is , where is the indiscrete group of integers and . Clearly, c is an -epimorphism. Hence, by Lemma 2, is bicoreflective in , but it does not contain the group .
Consider a finite cyclic semitpological group . The closure of in is a subgroup of and it is the smallest (with respect to inclusion) open neighborhood of 0. The same holds for the group of integers with a non- topology. Moreover, we have the following simple fact:
Lemma 3. Let G and H be cyclic semitopological groups, either finite or infinite and non-. Let be such that in G and in H. Consider the subgroup of . Then , where m is the least common multiple of n and k.
Proof. Let U be an open neighborhood of in . Then is open in . Therefore V (and hence also U) contains . Analogously, U contains . Hence U contains . Therefore every neighborhood of in contains . The subgroup is open in , since is open in . □
Clearly, the above lemma can be generalized to any finite number of groups.
The following proposition is a generalization of [
4] (Proposition 4.9).
Proposition 1. Let be an epireflective subcategory of such that and , where is the prime factorization of n. For , consider the group with the subspace topology induced from . Let be the natural number such that in . We define the subcategories and of as follows:
- 1.
If every cyclic group from of order is homeomorphic to with the subspace topology induced from or there exists a cyclic group (where ) from such that in , then let be the subcategory consisting precisely of those groups from that do not have an element of order .
- 2.
If the subgroup of is not indiscrete, let be the subcategory consisting precisely of such groups G from that if H is a cyclic subgroup of G of order , where , then the index of in H is less than .
Then and are maximal hereditary coreflective subcategories of that are not bicoreflective in .
Note that there does not need to be a subcategory or for every .
Proof. Clearly, the subcategories and are hereditary and, by Lemma 1, they are not bicoreflective in . The subcategories are coreflective in .
We need to show that also the subcategories are coreflective in . Let be a family of groups from for some , be an extremal -epimorphism and f be the homomorphism . Assume that G has a subgroup H homeomorphic to with the subspace topology induced from . Let x be an element of such that . Then the subgroup is also homeomorphic to . Without loss of generality we may assume that is a subgroup of , where each belongs to some . By Lemma 3, the topology of is coarser then the topology of , a contradiction.
Lastly we show that every hereditary coreflective subcategory of that is not bicoreflective in is contained in one of the subcategories or . If a subcategory is hereditary and coreflective in , but not bicoreflective in , then it does not contain the group . Therefore it does not contain one of its subgroups . Hence, it either does not contain a cyclic group of order (and then ) or it does not contain the group with . Then it also does not contain a cyclic group , where , with , and then . □
In [
4] we presented examples of such epireflective subcategories
of
that every hereditary coreflective subcategory of
that contains a group with a non-indiscrete topology is bicoreflective in
. Here we give another example of subcategories of
with this property. Note that if the subcategory
from the following example consists only of abelian groups, then we easily obtain the following result from the above proposition.
Example 2. Let be an epireflective subcategory of such that is the discrete cyclic group , where p is a prime number. Then every hereditary coreflective subcategory of that contains a group with a non-indiscrete topology is bicoreflective in . Let G be a non-indiscrete group from and U be an open neighborhood of such that . Choose an element . The order of x is p and the subgroup of G is discrete, therefore belongs to and is bicoreflective in .
Proposition 2. Let be an epireflective subcategory of such that and is the group of integers with the topology generated by its subgroups of the form , where , and P is a given set of prime numbers. Let and be the subcategory of consisting precisely of such groups G from that if H is an infinite cyclic subgroup of G then there exists an such that the subgroup of index is not open in H. Then those that contain a group with an element of infinite order are maximal hereditary coreflective subcategories of that are not bicoreflective in . If all contain only torsion groups, then they are all equal to the subcategory of all torsion groups from and is the largest hereditary coreflective subcategory of that is not bicoreflective in .
Proof. Obviously, the subcategory is hereditary and coreflective, but not bicoreflective in . If all subcategories contain only torsion groups, then for every group G from and every element of infinite order we have . Therefore every hereditary coreflective subcategory of that is not bicoreflective in is contained in and the subcategory is maximal with this property.
Now assume that at least one of the subcategories contains a group with an element of infinite order. Clearly, every subcategory is hereditary. It does not contain the group , and therefore, by Lemma 1, it is not bicoreflective in .
We show that the subcategories are coreflective in . Let , be a family of groups from and be an extremal -epimorphism. Let x be an element of such that the subgroup of index is open in for every . Then also the subgroup of index of is open in for every . Without loss of generality we may assume that is a subgroup of , where is the product with the usual topology and each belongs to some . For every there exists a natural number such that the subgroup of index is not open in . Then the subgroup of of index , where is the largest from , is not open in , a contradiction.
Next we show that every hereditary coreflective subcategory of that is not bicoreflective in is contained in some . Let be a hereditary coreflective subcategory of that is not bicoreflective in . Then does not contain the group . If contains only torsion groups, then for every . Otherwise contains the group of integers with a topology such that its subgroup of index is not open for some and . Therefore is contained in . □
Proposition 3. Let be an epireflective subcategory of such that and is the group of integers with a non- topology. Let the closure of in be the subgroup . Then the following holds:
- 1.
If the embedding is an -epimorphism, then the subcategory of all torsion groups from is the largest hereditary coreflective subcategory of that is not bicoreflective in .
- 2.
For every minimal natural number k such that and the embedding is not an -epimorphism let be the subcategory consisting of such groups G from that if H is a cyclic subgroup of G then the index of in H is at most . The subcategories are maximal hereditary coreflective subcategories of that are not bicoreflective in .
Assume that for every minimal natural number k such that and the embedding is not an -epimorphism, contains a finite cyclic group such that the index of in is greater than . Then the subcategory of all torsion groups from is also a maximal hereditary coreflective subcategory of that is not bicoreflective in .
Proof. Assume that the closure of in is the subgroup and the embedding is an -epimorphism. Clearly, the subcategory is hereditary and coreflective, but not bicoreflective in . We need to show that it is maximal with this property. Let be a hereditary coreflective subcategory of that contains the group Z with some topology and be the -coreflection of . Assume that . Let be the homomorphism given by . Then f is continuous. There exists a unique homomorphism such that . Hence and . Therefore c is an -epimorphism and, by Lemma 2, the subcategory is bicoreflective in .
Now assume that the embedding is not an -epimorphism. The subcategory is hereditary and coreflective in , but not bicoreflective in . Let k be minimal such that and the embedding is not an -epimorphism. Clearly, the subcategory is hereditary. For the -coreflection we have . Therefore it is not an epimorphism and is not bicoreflective in .
We need to show that is coreflective in . Let be a family of groups from , be an extremal -epimorphism and f be the homomorphism . Assume that x is an element of such that the index of in is greater than . Then also the index of in is greater than . Without loss of generality we may assume that is a subgroup of , where each is an element of some . The index of in is a divisor of for every . Then, by Lemma 3, the index of in is at most , a contradiction.
Lastly, we show that every hereditary coreflective subcategory of that is not bicoreflective in is contained in or . Let be a hereditary coreflective subcategory of that is not bicoreflective in . Let be the -coreflection of . If it is a trivial homomorphism, then is contained in . Otherwise , where k is minimal such that and the embedding is not an -epimorphism. Assume that G is a cyclic group from that does not belong to . Then the index of in G is greater than . Then contains the group of integers Z with a topology such that the index of in Z is greater than (a subgroup of ). Then there exists a homomorphism such that . Then also , a contradiction. Therefore is contained in . Note that if for some minimal natural number k such that and the embedding is not an -epimorphism, does not contain a finite cyclic group G such that the index of in G is greater than , then the subcategory is contained in , and therefore it is not maximal. □