Snapsolve any problem by taking a picture.
Try it in the Numerade app?
A 0.125 M formic acid solution, HCOOH, has a pH of 2.99 (25°C). Determine its K and pKa. Given a 0.0250 M HNO2 (nitrous acid) solution with a Ka of 4.6 x 10^4, determine its percent ionization: HNO2 → H2O + H3O+ + NO2-
Added by Albert C.
Step 1
99) = 7.94 x 10^(-3) M - Formic acid is a weak acid, so we can write the equilibrium reaction: HCOOH + H2O ⇌ H3O+ + HCOO- - The equilibrium constant expression is: Ka = [H3O+][HCOO-]/[HCOOH] - We can use the initial concentration of formic acid to calculate the Show more…
Show all steps