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Hypoiodous acid (HIO) is a weak acid that dissociates in water as follows: HIO(aq) + H2O(l) → H3O+(aq) + IO−(aq). A 0.12 M solution of hypoiodous acid has a pH of 5.71. Calculate the acid-dissociation constant (Ka) for this acid.
Added by Clara R.
Step 1
Given: pH = 5.71 [H3O+] = 10^(-pH) = 10^(-5.71) = 1.95 x 10^(-6) M [IO-] = [H3O+] = 1.95 x 10^(-6) M Show more…
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