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The following skeletal oxidation-reduction reaction occurs under acidic conditions. Write the balanced OXIDATION half reaction.\ NO + Sn$^{2+}$ $\longrightarrow$ Sn + NO$_3^-$
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In this case, we have Sn and NO3- as reactants. Sn is being oxidized, as it loses electrons and its oxidation state increases from 0 to +2. The half-reaction for oxidation is: Sn -> Sn^2+ + 2e^- NO3- is being reduced, as it gains electrons and its oxidation Show more…
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