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Question

When sodium sulfite solution is added to acidified potassium permanganate solution, the purple permanganate solution turns colourless. The net ionic half-cell reactions are: reduction half-cell reaction: MnO4-(aq) --> Mn2+(aq) Oxidation half-cell reaction: SO32-(aq) --> SO42-(aq) Write and balance the equation for the overall redox reaction (in acidic medium) using the half-reaction method. Show all work.

          
            When sodium sulfite solution is added to acidified potassium
permanganate solution, the purple permanganate solution turns
colourless.  The net ionic half-cell reactions are:
reduction half-cell reaction: MnO4-(aq)
--> Mn2+(aq)
Oxidation half-cell reaction: SO32-(aq)
--> SO42-(aq)
Write and balance the equation for the overall redox reaction
(in acidic medium) using the half-reaction method.  Show all
work.

Added by Sarah R.

Instant Answer

Step 1

- Reduction half-cell reaction: \( \text{MnO}_4^- \rightarrow \text{Mn}^{2+} \) - Oxidation half-cell reaction: \( \text{SO}_3^{2-} \rightarrow \text{SO}_4^{2-} \) Show more…

Show all steps

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Transcript

00:01 Hello students, in the question it is given that sodium sulphide is added to acid fat potassium permanganate then the purple colour of the permanganate solution become colourless.

00:11 Oxidation and reduction half reaction is given and we have to balance the orblodeodeodeox reaction.

00:17 First of all, let's see oxidation half reaction.

00:34 The reaction given is so3 -2 minus gase s -o -4 to minus gase s -o -4 to my first of all we have to balance oxygen atom.

00:53 For that we have to add a bottom molecule in the left hand side.

01:00 Now we have to balance the hydrogen atoms.

01:02 We have two hydrogen atoms here so we will add 2 h plus here.

01:11 Now we should balance a number of electrons in the left hand side and right hand side and for that we will add 2 electrons here.

01:21 Let's consider this as a number of electrons in the left hand side and right hand side.

01:23 Equation 1.

01:25 Now let's take the case of reduction half reaction.

01:42 The reaction given is mno4 minus is mn 2 plus.

01:57 Let's balance the oxygen atoms.

01:59 So for that we have to add 4 h2 molecules in the right hand side.

02:07 Now we have to balance hydrogen atoms.

02:09 For that we will add here we have 8 hydrogen so we will add.

02:13 So we will add, so we will be add 8h plus in the left hand side.

02:19 Now let's see the case of electrons...