00:02
Hi, in the given problem here, this is the current carrying conductor kept perpendicular to the plane of paper and the direction of current is perpendicularly out of the plane of paper.
00:17
This current in this conductor is given as 2 .0 ampere whose direction is outward.
00:27
Now, if we consider a coil, a circular coil, whose two segments, two opposite segments are carrying current like this.
00:40
In the lower segment, the direction of current is outward, and in the upper segment is this inward.
00:46
Means if we look at the face of the coil from this point here, from right side, the direction of current here in it will be clockwise.
00:58
As the direction of current will be clockwise means this phase towards the observer will be behaving like a south pole.
01:06
So the direction of magnetic field will be entering into it.
01:10
It means here this is the direction of magnetic field due to the current carrying coil.
01:18
And using clemmings left hand rule, the direction of magnetic field at the center of this coil due to this straight current carrying conductor is a upward in the plane of this coil that is in a direction upward.
01:38
The distance between the center of this coil and the current carrying straight conductor is given as r is equal to 2 .0 centimeter and the current carried by this coil is 0 .20 ampere.
02:00
The diameter.
02:01
The diameter of this circular coil is given as 2 .0 millimeter.
02:07
So the radius of this coil will be half of the diameter, half of the diameter means 2 .0 millimeter divided by 2 means this is 1 .0 millimeter or 1 .0 into 10 dash per minus 3 meter.
02:21
Similarly here, the distance of this observation point means the center of the coil from the straight current heading conductor is 2 .0 into 10 dash per minus 2 meter.
02:32
So in the first part of the problem, magnetic field, as we have to find the torque experienced by this circular coil due to the magnetic field of this straight current carrying conductor.
02:45
So to find this torque, first of all, we will find magnetic field due to the straight conductor at the center of current carrying coil.
03:12
And that will be given by by 10 severed law, which says b is equal to mu not by 4 pi into 2 i by r.
03:22
For mu not by 4 pi, this is 10 -dish 1 minus 7, tesla meter per ampere into 2 into 2 for the current in the state conductor divided by capital r, which is 2 into 10 dash par minus 2 canceling this 2.
03:38
Here this magnetic field comes out to be 2 into 10 dashpar minus 5 tesla.
03:46
Now under the influence of this magnetic field and here this is b1.
03:55
Now under the influence of this magnet field b1 as the angle between b1 and the plane of the coil that is 0 degree...