00:04
Okay, today we want to look at determining whether the species ohcl is polar based on its lure structure.
00:13
So the first thing we need to do is build our lewd structure.
00:17
So in order to start building our lewd structure, we need to know how many valence electrons are present in each of our atoms.
00:23
So if we use our periodic table, you can see that hydrogen has one, oxygen has six, chloride chlorine has seven.
00:30
So we have 14 total valence electrons to work with.
00:33
And the next step of building our lewd structure is to determine what our central atom will be.
00:40
So typically the halides and hydrogen will only form a single bond.
00:46
And so oxygen is a good example or the best species in this case to be the central atom.
00:52
Species like water have two bonds to it.
00:55
And so i think this is the most appropriate species.
00:57
So we start with oxygen and then we form a single bond to each of our atoms.
01:04
We know that hydrogen is satisfied with two electrons to complete its valent shell, but oxygen and chlorine need eight.
01:12
So now we can start adding lone pairs to each of our species.
01:15
I'm using a dashed line here instead of dots.
01:18
It's make it a little bit easier to see.
01:20
And actually, if we go through now in this case and count the number of electrons we used, you can see that it totals to 14.
01:27
So we don't have to add any double bonds to our species here.
01:31
And now, so to answer the question, we need to assess whether this species is polar or non -polar.
01:39
And to do that, we need to look at electronegativity.
01:42
So the greater the electronegativity, the more it depletes electron density from the species it's bonded to...