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Strontium- 90 is a dangerous by-product of atomic testing because it mimics the action of calcium in the body. It decays in two $\beta$ -emissions to give zirconium-90 (nuclear $\mathrm{mass}=89.8824 \mathrm{~g})$ (a) Write a balanced nuclear equation for the overall decay of $\mathrm{Sr}-90 .$ (b) Calculate $\Delta m$ in grams when one mole of $\mathrm{Sr}-90$ decays to $\mathrm{Zr}-90 .$ (c) How much energy (in $\mathrm{kJ}$ ) is given off by the decay of $6.50 \mathrm{mg}$ of $\mathrm{Sr}-90 ?$

   Strontium- 90 is a dangerous by-product of atomic testing because it mimics the action of calcium in the body. It decays in two $\beta$ -emissions to give zirconium-90 (nuclear $\mathrm{mass}=89.8824 \mathrm{~g})$
(a) Write a balanced nuclear equation for the overall decay of $\mathrm{Sr}-90 .$
(b) Calculate $\Delta m$ in grams when one mole of $\mathrm{Sr}-90$ decays to $\mathrm{Zr}-90 .$
(c) How much energy (in $\mathrm{kJ}$ ) is given off by the decay of $6.50 \mathrm{mg}$ of $\mathrm{Sr}-90 ?$

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Chemistry Principles and Reactions

Chemistry Principles and Reactions

William L.… 8th Edition

Chapter 18, Problem 44

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Step 1

As explained, a nucleus undergoing beta emission has the same mass number but the atomic number increases by one. Therefore, the balanced nuclear equation is: \[{}^{90}_{38}\mathrm{Sr} \rightarrow {}^{90}_{40}\mathrm{Zr} + 2({}^{0}_{-1}\mathrm{e})\] Show more…

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