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Q mcAT Equation 2 1- Show that the units of specific heat (c) are cal-.docx

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1. The document shows the calculation of specific heat (c) from the heat equation and derives that the units of specific heat are cal/g°C. 2. It asks which block, lead or copper, will require more heat to increase temperature by 70°C if they have the same initial temperature and mass. Lead has a lower specific heat than copper, so the lead block will require less heat. 3. It provides a problem to calculate the specific heat of a new alloy, given the mass of the alloy and aluminum calorimeter cup, initial and final temperatures, and the mass of water.

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Q mcAT Equation 2 1. Show that the units of specific heat (c) are cal/g.Co by solving Equation 2 for c and substituting the appropriate units for Q, m and ??. A 2.00-kg lead block and a 2.00-kg copper block have the same temperature of 22°C. You wish to heat both blocks to 92°C. Which of the following statements is correct (circle its identifying letter)? 2. The lead block will require more heat than the copper block The lead block will require less heat than the copper block. The two blocks will require the same amount of heat. a. b. c. Explain your answer. To determine the specific heat of a new metal alloy, a 0.200-kg sample of the alloy is heated to 350°C and then placed in a 0.350-kg aluminum calorimeter cup containing 0.500 kg of water at 15.0°C. If the equilibrium temperature of the system is 32.8°C, what is the specific heat of 3. alloy? Note that, because you are given no information about the thermal properties of the thermometer and stirrer, their presence may be ignored. the Solution 1. Q = m*c*dT Unit of Q = Unit of energy = Cal Unit of m = unit of mass = gm unit of dT = Unit of temperature = C c = Q/m*dT unit of c = [Q]/([m]*[dT]) Unit of c = cal/gm-C 2. Required heat is given by: Q = m*C*dT
given that m and dT are same for both lead and copper So required heat will be directly proportional to specific heat of material Now specific heat of copper =0.386 J/gm-C Specific heat of lead = 0.128 J/gm-C Since specific heat of lead is less than specific heat of copper, So lead will require less heat than copper Correct option is B. Please Upvote.

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Q mcAT Equation 2 1- Show that the units of specific heat (c) are cal-.docx

  • 1. Q mcAT Equation 2 1. Show that the units of specific heat (c) are cal/g.Co by solving Equation 2 for c and substituting the appropriate units for Q, m and ??. A 2.00-kg lead block and a 2.00-kg copper block have the same temperature of 22°C. You wish to heat both blocks to 92°C. Which of the following statements is correct (circle its identifying letter)? 2. The lead block will require more heat than the copper block The lead block will require less heat than the copper block. The two blocks will require the same amount of heat. a. b. c. Explain your answer. To determine the specific heat of a new metal alloy, a 0.200-kg sample of the alloy is heated to 350°C and then placed in a 0.350-kg aluminum calorimeter cup containing 0.500 kg of water at 15.0°C. If the equilibrium temperature of the system is 32.8°C, what is the specific heat of 3. alloy? Note that, because you are given no information about the thermal properties of the thermometer and stirrer, their presence may be ignored. the Solution 1. Q = m*c*dT Unit of Q = Unit of energy = Cal Unit of m = unit of mass = gm unit of dT = Unit of temperature = C c = Q/m*dT unit of c = [Q]/([m]*[dT]) Unit of c = cal/gm-C 2. Required heat is given by: Q = m*C*dT
  • 2. given that m and dT are same for both lead and copper So required heat will be directly proportional to specific heat of material Now specific heat of copper =0.386 J/gm-C Specific heat of lead = 0.128 J/gm-C Since specific heat of lead is less than specific heat of copper, So lead will require less heat than copper Correct option is B. Please Upvote.