Iridium(V) fluoride
Appearance
(Redirected from Iridium pentafluoride)
Names | |
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Other names
Iridium pentafluoride
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Identifiers | |
3D model (JSmol)
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Properties | |
IrF5 | |
Molar mass | 287.209 g/mol |
Appearance | yellow solid |
Melting point | 104.5 °C (220.1 °F; 377.6 K) |
Related compounds | |
Other cations
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Rhodium(V) fluoride, Osmium pentafluoride, Platinum(V) fluoride |
Related compounds
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Iridium(IV) fluoride, Iridium hexafluoride |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Iridium(V) fluoride, IrF5, is a chemical compound of iridium and fluorine. A highly reactive yellow low melting solid, it has a tetrameric structure, Ir4F20, which contains octahedrally coordinated iridium atoms.[1] This structure is shared with RuF5 and OsF5. It can be prepared by the controlled decomposition of IrF6[1] or the reduction of IrF6 with silicon powder or H2 in anhydrous HF.[2][3]
See also
[edit]References
[edit]- ^ a b Egon Wiberg, Arnold Frederick Holleman (2001) Inorganic Chemistry, Elsevier ISBN 0-12-352651-5
- ^ Paine, Robert T.; Asprey, Larned B. (1975). "Reductive syntheses of transition metal fluoride compounds. Synthesis of rhenium, osmium, and iridium pentafluorides and tetrafluorides". Inorganic Chemistry. 14 (5): 1111–1113. doi:10.1021/ic50147a030.
- ^ Bartlett, Neil; Rao, P. R. (1965). "Iridium pentafluoride". Chem. Commun. (12): 252–253. doi:10.1039/C19650000252.