1948 Iowa gubernatorial election
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 County results Beardsley: 40-50% 50–60% 60–70% 70–80% Switzer: 50–60% | |||||||||||||||||
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| Elections in Iowa |
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The 1948 Iowa gubernatorial election was held on November 2, 1948. Republican nominee William S. Beardsley defeated Democratic nominee Carroll O. Switzer with 55.68% of the vote.
Primary elections
[edit]Primary elections were held on June 7, 1948.[1]
Democratic primary
[edit]Candidates
[edit]- Carroll O. Switzer, Polk County Attorney
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Carroll O. Switzer | 56,195 | 100.00 | |
| Total votes | 56,195 | 100.00 | ||
Republican primary
[edit]Candidates
[edit]Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William S. Beardsley | 189,938 | 59.78 | |
| Republican | Robert D. Blue (incumbent) | 127,771 | 40.22 | |
| Total votes | 317,709 | 100.00 | ||
General election
[edit]Candidates
[edit]Major party candidates
- William S. Beardsley, Republican
- Carroll O. Switzer, Democratic
Other candidates
- C. E. Bierderman, Progressive
- Marvin Galbreath, Prohibition
- William F. Leonard, Socialist
Results
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | William S. Beardsley | 553,900 | 55.68% | ||
| Democratic | Carroll O. Switzer | 434,432 | 43.67% | ||
| Progressive | C. E. Bierderman | 3,570 | 0.36% | ||
| Prohibition | Marvin Galbreath | 2,458 | 0.25% | ||
| Socialist | William F. Leonard | 471 | 0.05% | ||
| Majority | 119,468 | ||||
| Turnout | 994,833 | ||||
| Republican hold | Swing | ||||
References
[edit]- ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1948. Retrieved April 9, 2020.
- ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1948. Retrieved April 9, 2020.