1. Introduction
Energy policy is a strategy in which the government decides to address the issues of energy development along with the development of the energy industry to sustain its growth, including energy production, distribution, and consumption [
1,
2]. The attributes of energy policy may include legislation, international treaties, and investment incentives [
3]. It plays a vital role in mitigating the impacts of global warming and the crisis of energy availability [
4].
Solar energy is one of the cleanest energy resources that does not compromise or add to global warming. The sun radiates more energy in one second than people have used since the beginning of time [
5,
6,
7]. Solar energy is often called “alternative energy” to fossil fuel energy sources such as oil and coal [
8]. The availability of cheap and abundant energy with minimum environmental and ecological hazards associated with its production and use is one of the important factors for desired improvement in the quality of life of the people [
9,
10]. The growing scarcity of fossil fuels has raised global interest in the harnessing of solar energy [
11]. Solar power is a type of energy with great future potential though at present it covers merely a minor portion of global energy demands (0.05% of the total primary energy supply); now PV power generates less than 1% of the total electricity supply [
12,
13,
14,
15]. This is due to solar power still being considered the most expensive type of renewable energy. However, in remote regions of the earth, it may very well constitute today's best solution for a decentralized energy supply. According to the 2010 BP Statistical Energy Survey, the world cumulative installed solar energy capacity was 22928.9 MW in 2009, a change of 46.9% compared to 2008.
World primary energy demand is projected in the Reference Scenario to expand by almost 60% from 2002 to 2030, an average annual increase of 1.7% per year. Demand will reach 16.5 billion tons of oil equivalents (toe) compared to 10.3 billion toes in 2002 which is shown in
Table 1. On the other hand, fossil fuels will continue to dominate global energy use. They will account for around 85% of the increase in world primary demand over 2002–2030. And their share in total demand will increase slightly, from 80% in 2002 to 82% in 2030. The share of renewable energy sources will remain flat at around 4%, while that of nuclear power will drop from 7% to 5% [
16,
17,
18,
19].
Solar photovoltaic technology could harness the sun's energy to provide large-scale, domestically secure, and environmentally friendly electricity [
20,
21,
22]. In 2005, global solar markets reached US
$ 11.8 billion, up 55% from 2004. Solar installations are expected to provide 15 GW in 2010 versus 2.7 GW in 2006. In April 2007, Photon Consulting forecasted 2010 revenues from sales of solar energy equipment of US
$ 90 billion, up from US
$ 20 billion in 2006. Demand for silicon for solar cells is expected to increase from 41,000 tons in 2006 to 120,000 tons in 2010 and 400,000 tons in 2014.
Table 2 shows the expected development and installation of solar photovoltaic electricity in the USA, Europe, Japan as well as worldwide until 2030.
Figure 1.
Solar PV Installation in the US from 2001 to 2019 (cumulative vs annual addition).
Figure 1.
Solar PV Installation in the US from 2001 to 2019 (cumulative vs annual addition).
With growing aspects of this emerging area, the future of solar energy technology promises a transition to greener, more sustainable, and energy-efficient manufacturing processes [
23]. As solar technologies continue to evolve and become more accessible, manufacturers will have the tools and incentives needed to make a substantial positive impact on both the environment and their bottom lines [
24,
25,
26]. This shift towards solar-powered manufacturing is not only a testament to the industry's commitment to sustainability but also a strategic move towards long-term economic competitiveness [
27].
The modern industrial landscape is witnessing a paradigm shift towards more sustainable and environmentally conscious practices, with a growing emphasis on green manufacturing. In this context, the utilization of solar energy stands as a pivotal and transformative component in the pursuit of cleaner, more energy-efficient production processes [
28,
29]. Solar energy offers not only a renewable and abundant source of power but also aligns with the principles of green manufacturing, which prioritize reduced environmental impact, energy efficiency, and resource conservation [
30].
In the realm of green manufacturing, the integration of circular economy principles offers a wealth of advantages by culminating in a holistic and sustainable approach [
31,
32,
33,
34,
35]. Green manufacturing, grounded in its commitment to reducing environmental impact and conserving resources, harmoniously dovetails with the foundational principles of the circular economy [
36]. By blending these two paradigms, manufacturers stand to benefit in multiple dimensions [
37]. Through the infusion of manufacturing process improvement principles, operations are streamlined, leading to increased efficiency, cost savings, and minimized waste generation. Furthermore, the incorporation of additive manufacturing techniques introduces unprecedented levels of flexibility, enabling on-demand production of intricate, sustainable components, and reducing material waste [
38,
39,
40,
41]. Simultaneously, the synergy of human-robot collaboration optimizes production processes by enhancing precision and speed, ultimately leading to cost reductions and heightened product quality [
41,
42,
43,
44]. This amalgamation promotes the life extension of products, facilitated by eco-design principles, and reduces the demand for virgin materials. The adoption of circular economy practices also entails the establishment of closed-loop systems and partnerships with suppliers and customers, which further enhances the overall sustainability of the supply chain, while enabling manufacturers to extract value from their waste materials. The reintegration of these materials into production operations, through waste-to-energy or upcycling approaches, not only minimizes environmental impact but also bolsters the circular economy's commitment to reducing waste. Sustainability metrics and reporting are integral to tracking progress, and the shift toward sustainable packaging materials and practices completes this sustainable loop [
37]. Ultimately, the integration of circular economy principles within green manufacturing exemplifies a win-win scenario: manufacturers benefit from enhanced operational efficiency, cost savings, and reduced environmental impact, while simultaneously contributing to global sustainability efforts by reducing waste and conserving resources. This dynamic synergy represents a pivotal step toward a greener, more responsible, and economically prosperous future for both businesses and society at large.
Particularly, the inclusion of Solar energy in the circular economy-based green manufacturing domain stands as an unequivocal environmental champion in the realm of sustainable development, serving as the linchpin of responsible energy generation [
45,
46,
47,
48]. Unlike conventional energy sources, it operates without depleting precious natural resources or releasing harmful gaseous emissions like CO2, NOx, SO2, or particulates, thus contributing to a reduction in greenhouse and toxic gases. Additionally, solar energy projects can play a vital role in land reclamation, breathing new life into previously degraded areas. Notably, the decentralized nature of solar energy production reduces the need for extensive electricity grid transmission lines, mitigating energy losses and infrastructure requirements [
49]. Simultaneously, solar power systems can enhance the quality of local water resources by conserving water traditionally consumed by cooling processes in conventional power plants. Solar energy further fosters regional and national energy independence by diversifying the energy mix and reducing dependence on centralized power sources. In turn, this diversification bolsters energy supply security and accelerates rural electrification efforts in developing nations, extending the benefits of clean energy access to underserved communities.
3. Result and Discussion
3.1. Question 01
For determining the mean and standard deviation, by month filter was applied and then the average and standard deviation of every month was taken. For the yearly mean and standard deviation, 8760 data were analyzed to get the values for 2014, 2015, and 2016.
Mean speed for 2015 = 4.875 m/s
Mean speed for 2014 = 5.07 m/s
Mean speed for 2016 = 5.15 m/s
Standard Deviation for 2015 = 2.6585
Standard Deviation for 2014 = 2.73
Standard Deviation for 2016 = 2.79
For the yearly mean and standard deviation for the year 2014, the rand () function in Excel was used to create a random sample and then 1000 data points were collected from that group. From the 1000 random data points, the month wise mean and standard deviation for 2014 was calculated and they are as follows:
Month |
Mean (M/S) |
Standard Deviation |
January |
6.09 |
2.93 |
February |
5.93 |
3.27 |
March |
5.29 |
2.86 |
April |
5.36 |
2.84 |
May |
4.41 |
2.75 |
June |
4.56 |
2.2 |
July |
4.18 |
2.09 |
August |
4.27 |
2.09 |
September |
4.10 |
2.09 |
October |
5.22 |
2.34 |
November |
4.49 |
2.52 |
December |
5.49 |
1.54 |
3.2. Question 02
Using Minitab to fit a random sample of 1000, we concluded that the Weibull distribution is the best fit but still has a low p-value of <0.01. The second-best distributions were normal distribution with a p-value <0.005.
Figure 2.
Probability plot of wind speed with normal distribution.
Figure 2.
Probability plot of wind speed with normal distribution.
Figure 3.
Probability plot of wind speed with exponential distribution.
Figure 3.
Probability plot of wind speed with exponential distribution.
Figure 4.
Probability plot of wind speed with lognormal distribution.
Figure 4.
Probability plot of wind speed with lognormal distribution.
Figure 5.
Probability plot of wind speed with Weibull distribution.
Figure 5.
Probability plot of wind speed with Weibull distribution.
3.3. Question 03
- ✔
Hypothesis testing on windspeed means, Null Hypothesis: Ho: uo = u1
- ✔
Alternative hypothesis: H1: uo≠u1
- ✔
The mean of the 1000 random value of wind speed of 2015 is = 4.85 m/s
- ✔
The variance of the 1000 random value of wind of 2015 speed is = 7.05
- ✔
Standard deviation = 2.64
- ✔
The mean of the 1000 random value of wind speed of 2016 is = 5.05m/s
- ✔
The variance of the 1000 random value of wind of 2016 speed is = 7.78 m/s
- ✔
Standard deviation = 2.78 m/s
- ✔
Sp= 2.72
- ✔
to = -0.51
- ✔
to falls in between the range. Hence, we fail to reject the null hypothesis. So, the mean wind speed is not significantly different between two adjacent years.
Here, F value is less than the F critical value, so we fail to reject the null hypothesis using 95% confidence level.
Figure 6.
F-test of two samples for variances.
Figure 6.
F-test of two samples for variances.
3.4. Question 04
We have taken 1000 sample data from the 8760 data to estimate the yearly wind speed. We have used Vh = Vg (80/8)3 to find the wind speed at turbine height. We have also removed the data which are unable to operate wind turbine. So, we have eliminated the wind speed less than 2m/s and greater than 25m/s. This gives us 330 data where wind turbine can operate between wind speed 12 m/s to 25 m/s.
The output will be = 2 MW/h*330 hrs. = 650 MWh. Between 0 to 2m/s numbers of samples = 32 Between 2 to 4m/s numbers of samples = 106 Between 4 to 6m/s numbers of samples = 134 Between 6 to 8m/s numbers of samples = 196 Between 8 to 10m/s numbers of samples = 150 Between 10 to 12m/s numbers of samples = 52
Wind Speed (m/s) |
12-25 |
10-12 |
8-10 |
6-8 |
4-6 |
2-4 |
Power (MW) |
2 |
1.75 |
1.5 |
1.25 |
0.75 |
0.25 |
From 1000 random data we have calculated total power =
(330Hrs x 2MWh) + (52Hrs x 1.75MWh) + (150Hrs x 1.5MWh) + (196Hrs x 1.25MWh) +
(134Hrs x .75MWh) + (106Hrs x .25MWh) = 1348 MWh total
For total 8760 data it will be = (1348/1000) *8760 = 11,808.48 MWh total
So, the number of homes wind turbine could power = (11,808.48*1000)/7300 = 1618 homes
3.5. Question 05
For PV output all-night data have been deleted and set the PV angle to the same as the latitude of NYC to maximize output. After calculating the sunrise and sunset time, excel was used to find solar irradiance at every hour. To find the power output I mapped the given data condition range of 1-9 to the required 1-0. Then the power output at every hour could be established for the panels. After power output at every hour was found the sum has been calculated and found the yearly power output.
In total, the solar panels generated 867.37 MWh.
Figure 7.
Sample calculation for question 5.
Figure 7.
Sample calculation for question 5.
3.6. Question 06
Using the second order of polynomial line, the equation for forecasting is:
For the linear fit model, equation is, y = 0.2608x + 14.732.
Figure 8.
Hourly wind speed forecasting for January 02, 2014.
Figure 8.
Hourly wind speed forecasting for January 02, 2014.
Figure 9.
Monthly wind speed forecasting for January 2014.
Figure 9.
Monthly wind speed forecasting for January 2014.
For monthly wind speed estimation, we averaged the daily windspeed for January 2014, using this data then plotted the daily windspeed average vs the day of the month. For a second-order polynomial trend line, the equation obtained is, y = 6E-06x2 - 0.0041x + 13.268
A linear trend line gives the equation: y = 0.0004x + 12.705.
Figure 10.
Yearly wind speed forecasting for January 2014.
Figure 10.
Yearly wind speed forecasting for January 2014.
For yearly wind speed, the average wind speed for every month for the year 2014 was calculated and plotted vs the number of the month. The formula for the second-degree polynomial is y = 0.0473x2 - 0.7101x + 7.0016
Using a Linear line of fit we got, y = -0.0949x + 5.5662.
3.7. Question 07
Factors that are significant and/or correlated:
Factor 1. The Size of PV system: The size of the PV is one of the important factors. The energy generation will increase with the PV size.
Factor 2. PV Capacity Cost: The cost is the most important factor that can be calculated by the multiplication of the number of PV panels and the installation cost. The equation is 106x. Here, x
= PV size in MW.
Factor 3. PV Efficiency: The PV efficiency has been selected as maximum as 25%. If we don’t care much about cost, the efficiency can be increased in a limited size.
Factor 4. Weather Condition: In perfect weather conditions, the factory needs 100,000 m2 panels to handle roughly 27 MW assuming each panel generates 270 W/m2. The angle of the sun and weather conditions have a great effect on the fluctuation of power, on average in NYC is 130 W/m2.
In January 2014 average weather condition in New York is 0.412 representing the solar cells generate about 41% of their maximum output during the day in winter. Whereas in summer the value is 0.453 or 45% of maximum generation
Factor 5 and 6. Ambient Temperature and Wind Speed: Ambient temperature and wind speed have also an effect on panel efficiency. Both are helping to cool down the PV systems, making them run more efficiently.
Factor 7. Hour of a Day: The power can be generated in daytime, not at night and the maximum power can be found at noon. Based on the formula, in January (winter) it is 1274.76 W/m2 and in summer it is 1468.6 W/m2.
Factor 8 & 9. Utility Pricing Scheme and Government Incentives: Utility scheme could offer an income possibility if the PV system is generating more power than it is consuming, and Government incentives could drastically lower the upfront price of panel installation.
Factor 10. The batter capacity: battery capacity can reduce the size of the PV system by storing energy when power generation is over the factory power usage and discharging it during bad weather or at night.
In winter, the factory has a peak energy draw of 17.4 MW during hours 13 and 16. So the expected power generation in January 1274.76 W × 25% × 1m2 × 0.412 × 1.0309 (from temperature) = 135.4.
In summer, 1468.6 W × 25% × 1m2 × 0.453 × 0.8621 = 143.4.
In winter, factory draws an average of 14.78 MW with a peak of 17.4 MW. Minimum we need
17.4 × 106/ 135.4 = 128,509 panels at 1 m2 each. In summer, minimum we need 22.6 × 106/143.4
= 157,602 panels at 1 m2 each.
If the panels make an average of 17.4 MW during the daytime (from hour 7 to 17), we can create
17.4 × 10 = 174 MWh per day. The factory needs 14.78 × 24 = 354.8 MWh. So, the system would need an average of 35.48 MW/hour for 10 hours to generate enough energy for daytime power draw peaks and night usage.
If we use a 60 MW system, simulation gives us average excess energy storage of 62.3 MW/day.
If a 510 MW battery is installed, it would take 510/62.3 = 8.2 day to fully charge and can be capable of providing a little over one day of full power outage.
3.8. Question 08
Life cycle cost analysis
Cost of Electricity by source in US
Power Plant Type |
Cost (LCOE) |
|
$/kW-hr |
Coal with CCS |
$0.12-0.13 |
CC Natural Gas |
$0.04 |
CC with CCS |
$0.08 |
Nuclear |
$0.09 |
Wind onshore |
$0.04 |
Wind offshore |
$0.11 |
Solar PV |
$0.04 |
Solar Thermal |
$0.17 |
Geothermal |
$0.04 |
Biomass |
$0.09 |
Hydro |
$0.03 |
(Levelized cost of electricity, LCOE) Source: Adapted from US DOE