1814 Rhode Island gubernatorial election
 | |||||||||||||||||
| |||||||||||||||||
| |||||||||||||||||
 County results Jones: 90–100% | |||||||||||||||||
| |||||||||||||||||
| Elections in Rhode Island |
|---|
 |
The 1814 Rhode Island gubernatorial election was held on 6 April 1814 in order to elect the governor of Rhode Island. Incumbent Federalist governor William Jones won re-election as he ran unopposed.[1]
General election
[edit]On election day, 6 April 1814, incumbent Federalist governor William Jones won re-election as he ran unopposed, thereby retaining Federalist control over the office of governor. Jones was sworn in for his fourth term on 7 May 1814.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Federalist | William Jones (incumbent) | 2,710 | 76.58 | |
| Scattering | 829 | 23.42 | ||
| Total votes | 3,539 | 100.00 | ||
| Federalist hold | ||||
References
[edit]- ^ "William Jones". National Governors Association. Retrieved 5 April 2024.
- ^ "RI Governor". ourcampaigns.com. 6 June 2005. Retrieved 5 April 2024.
Categories:
- 1814 Rhode Island elections
- Rhode Island gubernatorial elections
- 1814 in Rhode Island
- 1814 United States gubernatorial elections
- April 1814 events
- 1810s in Rhode Island
- 1810s Rhode Island elections
- 1814 elections
- 1814 elections in North America
- 1814 elections in the United States
- Government of Rhode Island
- United States gubernatorial elections in the 1810s
- Single-candidate elections